(H2O)2...H35Cl, state S ----------------------------------------- Fit frequencies(1) or differences(2) = 1 spin of nucleus 1 (units of 1/2) = 3 spin of nucleus 2 (units of 1/2) = 0 Number of iterations = -2 Excess in F and J over value in data = 2 Dump options (0,1,2,3) = 0 Freq. contributions options (0,1,2) = 0 Number of transitions = 6 ----------------------------------------- A = 0 6874.2687 B = 0 3197.9258 C = 0 2187.9090 DJ = 0 .009882 DJK = 0 -.00111 DK = 0 .0469 dJ = 0 .003313 dK = 0 .01990 HJ = 0 .000000 HJK = 0 .00000 HKJ = 0 .0000 HK = 0 .0000 hJ = 0 .000000000000 hJK = 0 .000000000000 hK = 0 .000000000000 LKKJ = 0 .000000000000 I1: X.aa = 0 -13.9680 I1: Xbb-Xcc = 0 -39.2372 I1: Xab = 0 35.35 I1: XJ.aa = 0 0.000000000000 I1: XK.aa = 0 0.000000000000 I1: XJ.b-c = 0 .000000000000 I1: Maa = 0 .000000000000 I1: Mbb-Mcc = 0 .000000000000 I1: Trace(M) = 0 .000000000000 I1: X.d = 0 .000000000000 --not used-- = 0 .000000000000 --not used-- = 0 .000000000000 --not used-- = 0 .000000000000 --not used-- = 0 .000000000000 --not used-- = 0 .000000000000 mu.a = 1 2.232642 mu.b = 1 0.661399 mu.c = 0 .0 d = 0 26.93 k = 0 0.0 2 1 1 1 1 0 7 1 5 1 11781.6270 0. 5000. 2 20 ,,, 2 1 1 1 1 0 7 3 5 3 11781.6270 0. 8750. 2 20 ,,, 3 1 3 2 1 2 7 1 5 1 14537.0098 0. 10000. 2 20 ,,, 3 1 3 2 1 2 7 3 5 3 14537.0098 0. 10000. 2 20 ,,, 3 1 3 2 1 2 9 1 7 1 14538.1386 0. 10000. 2 20 ,,, 3 1 3 2 1 2 9 3 7 3 14538.1386 0. 10000. 2 20 -2.5 , 2.5 ,