____________________________________________________________________________ | | | QSTARK - Fully diagonalizing fit of Stark shifts in a rotor | | with zero or one quadrupolar nuclei | |____________________________________________________________________________| version 6.IX.2005 Zbigniew KISIEL ------------------------------------------------------------------------------ OCS, first calibration (18.II.2000) ------------------------------------------------------------------------------ Calculation for J and F exceeding the value in data by at least 2 The fit will be made to TRANSITION FREQUENCIES 17 Lines read in 11 Lines fitted ---> 1 field free and 10 at non-zero field 1 Constants fitted TRANSITIONS (F and MF in units of 1/2): J K K <- J K K F MF<- F MF Volts Obs Obs-Calc Calc Field Field**2 -1 +1 -1 +1 ! ! zero field line ! 1. 1 0 1 0 0 0 2 0 0 0 0.0 12162.97900 0.00010 12162.9789 0.0000 0.00 ! ! DeltaM = 0 ! 2. 1 0 1 0 0 0 2 0 0 0 3140.4 12163.05960 0.00317 12163.0564 116.7915 13640.26 3. 1 0 1 0 0 0 2 0 0 0 3654.7 12163.08870 0.00480 12163.0839 135.9183 18473.80 4. 1 0 1 0 0 0 2 0 0 0 4140.7 12163.11560 0.00191 12163.1137 153.9927 23713.75 5. 1 0 1 0 0 0 2 0 0 0 6103.3 12163.27340 0.00166 12163.2717 226.9818 51520.75 6. 1 0 1 0 0 0 2 0 0 0 7850.6 12163.46360 0.00019 12163.4634 291.9639 85242.94 7. 1 0 1 0 0 0 2 0 0 0 9164.1 12163.63830 -0.00079 12163.6391 340.8130 116153.51 8. 1 0 1 0 0 0 2 0 0 0 10580.3 12163.85580 -0.00310 12163.8589 393.4815 154827.70 9. 1 0 1 0 0 0 2 0 0 0 12105.0 0.00000 -12164.13079-- 12164.1308 450.1851 202666.65 10. 1 0 1 0 0 0 2 0 0 0 13450.0 0.00000 -12164.40097-- 12164.4010 500.2057 250205.75 ! ! Delta M = 1 ! 11. 1 0 1 0 0 0 2 2 0 0 3140.4 12163.02140 0.00858-- 12163.0128 116.7915 13640.26 12. 1 0 1 0 0 0 2 2 0 0 4140.7 12163.04440 0.00653-- 12163.0379 153.9927 23713.75 13. 1 0 1 0 0 0 2 2 0 0 6103.3 12163.11110 0.00409 12163.1070 226.9818 51520.75 14. 1 0 1 0 0 0 2 2 0 0 7850.6 12163.19330 0.00243 12163.1909 291.9639 85242.94 15. 1 0 1 0 0 0 2 2 0 0 9164.1 12163.26990 0.00217 12163.2677 340.8130 116153.51 16. 1 0 1 0 0 0 2 2 0 0 12105.0 0.00000 -12163.48285-- 12163.4828 450.1851 202666.65 17. 1 0 1 0 0 0 2 2 0 0 13450.0 0.00000 -12163.60105-- 12163.6011 500.2057 250205.75 Standard deviation = 0.002777 ITERATION NO = 3 CONSTANTS, deviations and changes: d = 26.888937662 +- 0.028546226 -0.000000001 FINAL RESULTS OF LEAST SQUARES FITTING PROCEDURE ================================================ FITTED CONSTANTS: A /MHz 9000000. 1:Xab /MHz 0. B /MHz 6081.492049999999835 1:XJ.a/kHz 0. C /MHz 0. 1:XK.a/kHz 0. DJ /kHz 1.3008 1:XJbc/kHz 0. DJK /kHz 0. 1:Ma /MHz 0. DK /kHz 0. 1:Mb-c/MHz 0. dJ /kHz 0. 1:Tr /MHz 0. dK /kHz 0. 1:Xd /kHz 0. HJ / Hz 0. HJK / Hz 0. HKJ / Hz 0. HK / Hz 0. hJ / Hz 0. hJK / Hz 0. Mu.a /D 0.715196000000000 hK / Hz 0. Mu.b /D 0. LKKJ /mHz 0. Mu.c /D 0. 1:Xa /MHz 0. d /cm 26.888(28) 1:Xb-c/MHz 0. k /cm 0. ------------------------------------------------------------------------------